-6(3x-2)+8x=6(x+4)

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Solution for -6(3x-2)+8x=6(x+4) equation: 



-6(3x-2)+8x=6(x+4)

We move all terms to the left:

-6(3x-2)+8x-(6(x+4))=0

We add all the numbers together, and all the variables

8x-6(3x-2)-(6(x+4))=0

We multiply parentheses

8x-18x-(6(x+4))+12=0



We calculate terms in parentheses: -(6(x+4)), so:

6(x+4)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We add all the numbers together, and all the variables

-10x-(6x+24)+12=0

We get rid of parentheses

-10x-6x-24+12=0

We add all the numbers together, and all the variables

-16x-12=0

We move all terms containing x to the left, all other terms to the right

-16x=12

x=12/-16

x=-3/4

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