-6(3x-2)=10(x-2)

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Solution for -6(3x-2)=10(x-2) equation: 



-6(3x-2)=10(x-2)

We move all terms to the left:

-6(3x-2)-(10(x-2))=0

We multiply parentheses

-18x-(10(x-2))+12=0



We calculate terms in parentheses: -(10(x-2)), so:

10(x-2)

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

-18x-10x+20+12=0

We add all the numbers together, and all the variables

-28x+32=0

We move all terms containing x to the left, all other terms to the right

-28x=-32

x=-32/-28

x=1+1/7

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