-6(3x-2)=7(x+8)+6

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Solution for -6(3x-2)=7(x+8)+6 equation: 



-6(3x-2)=7(x+8)+6

We move all terms to the left:

-6(3x-2)-(7(x+8)+6)=0

We multiply parentheses

-18x-(7(x+8)+6)+12=0



We calculate terms in parentheses: -(7(x+8)+6), so:

7(x+8)+6

We multiply parentheses

7x+56+6

We add all the numbers together, and all the variables

7x+62

Back to the equation:

-(7x+62)



We get rid of parentheses

-18x-7x-62+12=0

We add all the numbers together, and all the variables

-25x-50=0

We move all terms containing x to the left, all other terms to the right

-25x=50

x=50/-25

x=-2

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