-6(3x-5)+10(-1-4x)=-38

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Solution for -6(3x-5)+10(-1-4x)=-38 equation:



-6(3x-5)+10(-1-4x)=-38
We move all terms to the left:
-6(3x-5)+10(-1-4x)-(-38)=0
We add all the numbers together, and all the variables
-6(3x-5)+10(-4x-1)-(-38)=0
We add all the numbers together, and all the variables
-6(3x-5)+10(-4x-1)+38=0
We multiply parentheses
-18x-40x+30-10+38=0
We add all the numbers together, and all the variables
-58x+58=0
We move all terms containing x to the left, all other terms to the right
-58x=-58
x=-58/-58
x=1

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