-6(3x-5)+10(-1-4x)=-38

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Solution for -6(3x-5)+10(-1-4x)=-38 equation: 



-6(3x-5)+10(-1-4x)=-38

We move all terms to the left:

-6(3x-5)+10(-1-4x)-(-38)=0

We add all the numbers together, and all the variables

-6(3x-5)+10(-4x-1)-(-38)=0

We add all the numbers together, and all the variables

-6(3x-5)+10(-4x-1)+38=0

We multiply parentheses

-18x-40x+30-10+38=0

We add all the numbers together, and all the variables

-58x+58=0

We move all terms containing x to the left, all other terms to the right

-58x=-58

x=-58/-58

x=1

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