-6(3z+19)=-6z+6

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Solution for -6(3z+19)=-6z+6 equation: 



-6(3z+19)=-6z+6

We move all terms to the left:

-6(3z+19)-(-6z+6)=0

We multiply parentheses

-18z-(-6z+6)-114=0

We get rid of parentheses

-18z+6z-6-114=0

We add all the numbers together, and all the variables

-12z-120=0

We move all terms containing z to the left, all other terms to the right

-12z=120

z=120/-12

z=-10

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