-6(4+2c)+-5=8c+51

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Solution for -6(4+2c)+-5=8c+51 equation: 



-6(4+2c)+-5=8c+51

We move all terms to the left:

-6(4+2c)+-5-(8c+51)=0

We add all the numbers together, and all the variables

-6(2c+4)-(8c+51)-5+=0

We add all the numbers together, and all the variables

-6(2c+4)-(8c+51)=0

We multiply parentheses

-12c-(8c+51)-24=0

We get rid of parentheses

-12c-8c-51-24=0

We add all the numbers together, and all the variables

-20c-75=0

We move all terms containing c to the left, all other terms to the right

-20c=75

c=75/-20

c=-3+3/4

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