-6(4+3b)-6(1+7b)=30

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Solution for -6(4+3b)-6(1+7b)=30 equation: 



-6(4+3b)-6(1+7b)=30

We move all terms to the left:

-6(4+3b)-6(1+7b)-(30)=0

We add all the numbers together, and all the variables

-6(3b+4)-6(7b+1)-30=0

We multiply parentheses

-18b-42b-24-6-30=0

We add all the numbers together, and all the variables

-60b-60=0

We move all terms containing b to the left, all other terms to the right

-60b=60

b=60/-60

b=-1

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