-6(6y-3)+2=-36y+20

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Solution for -6(6y-3)+2=-36y+20 equation: 



-6(6y-3)+2=-36y+20

We move all terms to the left:

-6(6y-3)+2-(-36y+20)=0

We multiply parentheses

-36y-(-36y+20)+18+2=0

We get rid of parentheses

-36y+36y-20+18+2=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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