-6(7+1)+8u=2(u-3)

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Solution for -6(7+1)+8u=2(u-3) equation: 



-6(7+1)+8u=2(u-3)

We move all terms to the left:

-6(7+1)+8u-(2(u-3))=0

We add all the numbers together, and all the variables

8u-(2(u-3))-68=0



We calculate terms in parentheses: -(2(u-3)), so:

2(u-3)

We multiply parentheses

2u-6

Back to the equation:

-(2u-6)



We get rid of parentheses

8u-2u+6-68=0

We add all the numbers together, and all the variables

6u-62=0

We move all terms containing u to the left, all other terms to the right

6u=62

u=62/6

u=10+1/3

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