-6(8-x)-8(x-3)=-40

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Solution for -6(8-x)-8(x-3)=-40 equation: 



-6(8-x)-8(x-3)=-40

We move all terms to the left:

-6(8-x)-8(x-3)-(-40)=0

We add all the numbers together, and all the variables

-6(-1x+8)-8(x-3)-(-40)=0

We add all the numbers together, and all the variables

-6(-1x+8)-8(x-3)+40=0

We multiply parentheses

6x-8x-48+24+40=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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