-6(b-4)=4(1-b)+2

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Solution for -6(b-4)=4(1-b)+2 equation: 



-6(b-4)=4(1-b)+2

We move all terms to the left:

-6(b-4)-(4(1-b)+2)=0

We add all the numbers together, and all the variables

-6(b-4)-(4(-1b+1)+2)=0

We multiply parentheses

-6b-(4(-1b+1)+2)+24=0



We calculate terms in parentheses: -(4(-1b+1)+2), so:

4(-1b+1)+2

We multiply parentheses

-4b+4+2

We add all the numbers together, and all the variables

-4b+6

Back to the equation:

-(-4b+6)



We get rid of parentheses

-6b+4b-6+24=0

We add all the numbers together, and all the variables

-2b+18=0

We move all terms containing b to the left, all other terms to the right

-2b=-18

b=-18/-2

b=+9

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