-6(c+2)+2c=6(2c-1)

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Solution for -6(c+2)+2c=6(2c-1) equation:


Simplifying
-6(c + 2) + 2c = 6(2c + -1)

Reorder the terms:
-6(2 + c) + 2c = 6(2c + -1)
(2 * -6 + c * -6) + 2c = 6(2c + -1)
(-12 + -6c) + 2c = 6(2c + -1)

Combine like terms: -6c + 2c = -4c
-12 + -4c = 6(2c + -1)

Reorder the terms:
-12 + -4c = 6(-1 + 2c)
-12 + -4c = (-1 * 6 + 2c * 6)
-12 + -4c = (-6 + 12c)

Solving
-12 + -4c = -6 + 12c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12c' to each side of the equation.
-12 + -4c + -12c = -6 + 12c + -12c

Combine like terms: -4c + -12c = -16c
-12 + -16c = -6 + 12c + -12c

Combine like terms: 12c + -12c = 0
-12 + -16c = -6 + 0
-12 + -16c = -6

Add '12' to each side of the equation.
-12 + 12 + -16c = -6 + 12

Combine like terms: -12 + 12 = 0
0 + -16c = -6 + 12
-16c = -6 + 12

Combine like terms: -6 + 12 = 6
-16c = 6

Divide each side by '-16'.
c = -0.375

Simplifying
c = -0.375

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