-6(i-2)+4(3-6i)=-36

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Solution for -6(i-2)+4(3-6i)=-36 equation:



-6(i-2)+4(3-6i)=-36
We move all terms to the left:
-6(i-2)+4(3-6i)-(-36)=0
We add all the numbers together, and all the variables
-6(i-2)+4(-6i+3)-(-36)=0
We add all the numbers together, and all the variables
-6(i-2)+4(-6i+3)+36=0
We multiply parentheses
-6i-24i+12+12+36=0
We add all the numbers together, and all the variables
-30i+60=0
We move all terms containing i to the left, all other terms to the right
-30i=-60
i=-60/-30
i=+2

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