-6(i-2)+4(3-6i)=-36

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Solution for -6(i-2)+4(3-6i)=-36 equation: 



-6(i-2)+4(3-6i)=-36

We move all terms to the left:

-6(i-2)+4(3-6i)-(-36)=0

We add all the numbers together, and all the variables

-6(i-2)+4(-6i+3)-(-36)=0

We add all the numbers together, and all the variables

-6(i-2)+4(-6i+3)+36=0

We multiply parentheses

-6i-24i+12+12+36=0

We add all the numbers together, and all the variables

-30i+60=0

We move all terms containing i to the left, all other terms to the right

-30i=-60

i=-60/-30

i=+2

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