-6(m+3)=2(4m+40)

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Solution for -6(m+3)=2(4m+40) equation: 



-6(m+3)=2(4m+40)

We move all terms to the left:

-6(m+3)-(2(4m+40))=0

We multiply parentheses

-6m-(2(4m+40))-18=0



We calculate terms in parentheses: -(2(4m+40)), so:

2(4m+40)

We multiply parentheses

8m+80

Back to the equation:

-(8m+80)



We get rid of parentheses

-6m-8m-80-18=0

We add all the numbers together, and all the variables

-14m-98=0

We move all terms containing m to the left, all other terms to the right

-14m=98

m=98/-14

m=-7

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