-6(n-2)=-3(4n-4)+n

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Solution for -6(n-2)=-3(4n-4)+n equation: 



-6(n-2)=-3(4n-4)+n

We move all terms to the left:

-6(n-2)-(-3(4n-4)+n)=0

We multiply parentheses

-6n-(-3(4n-4)+n)+12=0



We calculate terms in parentheses: -(-3(4n-4)+n), so:

-3(4n-4)+n

We add all the numbers together, and all the variables

n-3(4n-4)

We multiply parentheses

n-12n+12

We add all the numbers together, and all the variables

-11n+12

Back to the equation:

-(-11n+12)



We get rid of parentheses

-6n+11n-12+12=0

We add all the numbers together, and all the variables

5n=0

n=0/5

n=0

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