-6(n-3)=3(n-9)

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Solution for -6(n-3)=3(n-9) equation: 



-6(n-3)=3(n-9)

We move all terms to the left:

-6(n-3)-(3(n-9))=0

We multiply parentheses

-6n-(3(n-9))+18=0



We calculate terms in parentheses: -(3(n-9)), so:

3(n-9)

We multiply parentheses

3n-27

Back to the equation:

-(3n-27)



We get rid of parentheses

-6n-3n+27+18=0

We add all the numbers together, and all the variables

-9n+45=0

We move all terms containing n to the left, all other terms to the right

-9n=-45

n=-45/-9

n=+5

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