-6(p+2)-p-4=-7(p+4)+12

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Solution for -6(p+2)-p-4=-7(p+4)+12 equation: 



-6(p+2)-p-4=-7(p+4)+12

We move all terms to the left:

-6(p+2)-p-4-(-7(p+4)+12)=0

We add all the numbers together, and all the variables

-1p-6(p+2)-(-7(p+4)+12)-4=0

We multiply parentheses

-1p-6p-(-7(p+4)+12)-12-4=0



We calculate terms in parentheses: -(-7(p+4)+12), so:

-7(p+4)+12

We multiply parentheses

-7p-28+12

We add all the numbers together, and all the variables

-7p-16

Back to the equation:

-(-7p-16)



We add all the numbers together, and all the variables

-7p-(-7p-16)-16=0

We get rid of parentheses

-7p+7p+16-16=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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