-6(p+2)-p-4=-7(p+4)+12

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Solution for -6(p+2)-p-4=-7(p+4)+12 equation:



-6(p+2)-p-4=-7(p+4)+12
We move all terms to the left:
-6(p+2)-p-4-(-7(p+4)+12)=0
We add all the numbers together, and all the variables
-1p-6(p+2)-(-7(p+4)+12)-4=0
We multiply parentheses
-1p-6p-(-7(p+4)+12)-12-4=0
We calculate terms in parentheses: -(-7(p+4)+12), so:
-7(p+4)+12
We multiply parentheses
-7p-28+12
We add all the numbers together, and all the variables
-7p-16
Back to the equation:
-(-7p-16)
We add all the numbers together, and all the variables
-7p-(-7p-16)-16=0
We get rid of parentheses
-7p+7p+16-16=0
We add all the numbers together, and all the variables
=0
p=0/1
p=0

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