-6(u+3)=2u-3+3(2u+1)

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Solution for -6(u+3)=2u-3+3(2u+1) equation: 



-6(u+3)=2u-3+3(2u+1)

We move all terms to the left:

-6(u+3)-(2u-3+3(2u+1))=0

We multiply parentheses

-6u-(2u-3+3(2u+1))-18=0



We calculate terms in parentheses: -(2u-3+3(2u+1)), so:

2u-3+3(2u+1)

determiningTheFunctionDomain
2u+3(2u+1)-3

We multiply parentheses

2u+6u+3-3

We add all the numbers together, and all the variables

8u

Back to the equation:

-(8u)



We add all the numbers together, and all the variables

-14u-18=0

We move all terms containing u to the left, all other terms to the right

-14u=18

u=18/-14

u=-1+2/7

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