-6(u-5)=3u+12

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Solution for -6(u-5)=3u+12 equation: 



-6(u-5)=3u+12

We move all terms to the left:

-6(u-5)-(3u+12)=0

We multiply parentheses

-6u-(3u+12)+30=0

We get rid of parentheses

-6u-3u-12+30=0

We add all the numbers together, and all the variables

-9u+18=0

We move all terms containing u to the left, all other terms to the right

-9u=-18

u=-18/-9

u=+2

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