-6(v+2)=2v-8+2(5v+6)

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Solution for -6(v+2)=2v-8+2(5v+6) equation: 



-6(v+2)=2v-8+2(5v+6)

We move all terms to the left:

-6(v+2)-(2v-8+2(5v+6))=0

We multiply parentheses

-6v-(2v-8+2(5v+6))-12=0



We calculate terms in parentheses: -(2v-8+2(5v+6)), so:

2v-8+2(5v+6)

determiningTheFunctionDomain
2v+2(5v+6)-8

We multiply parentheses

2v+10v+12-8

We add all the numbers together, and all the variables

12v+4

Back to the equation:

-(12v+4)



We get rid of parentheses

-6v-12v-4-12=0

We add all the numbers together, and all the variables

-18v-16=0

We move all terms containing v to the left, all other terms to the right

-18v=16

v=16/-18

v=-8/9

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