-6(v+2)=6v-2+2(3v+3)

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Solution for -6(v+2)=6v-2+2(3v+3) equation: 



-6(v+2)=6v-2+2(3v+3)

We move all terms to the left:

-6(v+2)-(6v-2+2(3v+3))=0

We multiply parentheses

-6v-(6v-2+2(3v+3))-12=0



We calculate terms in parentheses: -(6v-2+2(3v+3)), so:

6v-2+2(3v+3)

determiningTheFunctionDomain
6v+2(3v+3)-2

We multiply parentheses

6v+6v+6-2

We add all the numbers together, and all the variables

12v+4

Back to the equation:

-(12v+4)



We get rid of parentheses

-6v-12v-4-12=0

We add all the numbers together, and all the variables

-18v-16=0

We move all terms containing v to the left, all other terms to the right

-18v=16

v=16/-18

v=-8/9

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