-6(w+1)=2w-4+5(2w+2)

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Solution for -6(w+1)=2w-4+5(2w+2) equation: 



-6(w+1)=2w-4+5(2w+2)

We move all terms to the left:

-6(w+1)-(2w-4+5(2w+2))=0

We multiply parentheses

-6w-(2w-4+5(2w+2))-6=0



We calculate terms in parentheses: -(2w-4+5(2w+2)), so:

2w-4+5(2w+2)

determiningTheFunctionDomain
2w+5(2w+2)-4

We multiply parentheses

2w+10w+10-4

We add all the numbers together, and all the variables

12w+6

Back to the equation:

-(12w+6)



We get rid of parentheses

-6w-12w-6-6=0

We add all the numbers together, and all the variables

-18w-12=0

We move all terms containing w to the left, all other terms to the right

-18w=12

w=12/-18

w=-2/3

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