-6(w+1)=2w-5+2(2w+1)

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Solution for -6(w+1)=2w-5+2(2w+1) equation: 



-6(w+1)=2w-5+2(2w+1)

We move all terms to the left:

-6(w+1)-(2w-5+2(2w+1))=0

We multiply parentheses

-6w-(2w-5+2(2w+1))-6=0



We calculate terms in parentheses: -(2w-5+2(2w+1)), so:

2w-5+2(2w+1)

determiningTheFunctionDomain
2w+2(2w+1)-5

We multiply parentheses

2w+4w+2-5

We add all the numbers together, and all the variables

6w-3

Back to the equation:

-(6w-3)



We get rid of parentheses

-6w-6w+3-6=0

We add all the numbers together, and all the variables

-12w-3=0

We move all terms containing w to the left, all other terms to the right

-12w=3

w=3/-12

w=-1/4

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