-6(x+10)3x=300

Solution for -6(x+10)3x=300 equation:

-6(x+10)3x=300

We move all terms to the left:

-6(x+10)3x-(300)=0

We multiply parentheses

-18x^2-180x-300=0

a = -18; b = -180; c = -300;
Δ = b2-4ac
Δ = -1802-4·(-18)·(-300)
Δ = 10800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10800}=\sqrt{3600*3}=\sqrt{3600}*\sqrt{3}=60\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-60\sqrt{3}}{2*-18}=\frac{180-60\sqrt{3}}{-36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+60\sqrt{3}}{2*-18}=\frac{180+60\sqrt{3}}{-36}
$