-6(x-2)+3=-3(x+3)+21

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Solution for -6(x-2)+3=-3(x+3)+21 equation: 



-6(x-2)+3=-3(x+3)+21

We move all terms to the left:

-6(x-2)+3-(-3(x+3)+21)=0

We multiply parentheses

-6x-(-3(x+3)+21)+12+3=0



We calculate terms in parentheses: -(-3(x+3)+21), so:

-3(x+3)+21

We multiply parentheses

-3x-9+21

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

-6x-(-3x+12)+15=0

We get rid of parentheses

-6x+3x-12+15=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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