-6(x-2)+4(3x-12)=68

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Solution for -6(x-2)+4(3x-12)=68 equation:



-6(x-2)+4(3x-12)=68
We move all terms to the left:
-6(x-2)+4(3x-12)-(68)=0
We multiply parentheses
-6x+12x+12-48-68=0
We add all the numbers together, and all the variables
6x-104=0
We move all terms containing x to the left, all other terms to the right
6x=104
x=104/6
x=17+1/3

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