-6(x-2)+4(3x-12)=68

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Solution for -6(x-2)+4(3x-12)=68 equation: 



-6(x-2)+4(3x-12)=68

We move all terms to the left:

-6(x-2)+4(3x-12)-(68)=0

We multiply parentheses

-6x+12x+12-48-68=0

We add all the numbers together, and all the variables

6x-104=0

We move all terms containing x to the left, all other terms to the right

6x=104

x=104/6

x=17+1/3

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