-6(x-2)=5(-x+2x)-32

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Solution for -6(x-2)=5(-x+2x)-32 equation: 



-6(x-2)=5(-x+2x)-32

We move all terms to the left:

-6(x-2)-(5(-x+2x)-32)=0

We add all the numbers together, and all the variables

-6(x-2)-(5(+x)-32)=0

We multiply parentheses

-6x-(5(+x)-32)+12=0



We calculate terms in parentheses: -(5(+x)-32), so:

5(+x)-32

We multiply parentheses

5x-32

Back to the equation:

-(5x-32)



We get rid of parentheses

-6x-5x+32+12=0

We add all the numbers together, and all the variables

-11x+44=0

We move all terms containing x to the left, all other terms to the right

-11x=-44

x=-44/-11

x=+4

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