-6(y+1)+4(3y-4)=5(y-6)+9

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Solution for -6(y+1)+4(3y-4)=5(y-6)+9 equation:



-6(y+1)+4(3y-4)=5(y-6)+9
We move all terms to the left:
-6(y+1)+4(3y-4)-(5(y-6)+9)=0
We multiply parentheses
-6y+12y-(5(y-6)+9)-6-16=0
We calculate terms in parentheses: -(5(y-6)+9), so:
5(y-6)+9
We multiply parentheses
5y-30+9
We add all the numbers together, and all the variables
5y-21
Back to the equation:
-(5y-21)
We add all the numbers together, and all the variables
6y-(5y-21)-22=0
We get rid of parentheses
6y-5y+21-22=0
We add all the numbers together, and all the variables
y-1=0
We move all terms containing y to the left, all other terms to the right
y=1

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