-6(y+1)+8y=2(y-3

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Solution for -6(y+1)+8y=2(y-3 equation: 



-6(y+1)+8y=2(y-3

We move all terms to the left:

-6(y+1)+8y-(2(y-3)=0

We add all the numbers together, and all the variables

8y-6(y+1)-(2(y-3)=0

We multiply parentheses

8y-6y-(2(y-3)-6=0

We add all the numbers together, and all the variables

2y-(2(y-3)-6=0

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