-6(y+1)+8y=2(y-3)

Solution for -6(y+1)+8y=2(y-3) equation:

Simplifying
-6(y + 1) + 8y = 2(y + -3)

Reorder the terms:
-6(1 + y) + 8y = 2(y + -3)
(1 * -6 + y * -6) + 8y = 2(y + -3)
(-6 + -6y) + 8y = 2(y + -3)

Combine like terms: -6y + 8y = 2y
-6 + 2y = 2(y + -3)

Reorder the terms:
-6 + 2y = 2(-3 + y)
-6 + 2y = (-3 * 2 + y * 2)
-6 + 2y = (-6 + 2y)

Add '6' to each side of the equation.
-6 + 6 + 2y = -6 + 6 + 2y

Combine like terms: -6 + 6 = 0
0 + 2y = -6 + 6 + 2y
2y = -6 + 6 + 2y

Combine like terms: -6 + 6 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.