-6(y+2)+4(3y-4)=5(y-4)+8

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Solution for -6(y+2)+4(3y-4)=5(y-4)+8 equation: 



-6(y+2)+4(3y-4)=5(y-4)+8

We move all terms to the left:

-6(y+2)+4(3y-4)-(5(y-4)+8)=0

We multiply parentheses

-6y+12y-(5(y-4)+8)-12-16=0



We calculate terms in parentheses: -(5(y-4)+8), so:

5(y-4)+8

We multiply parentheses

5y-20+8

We add all the numbers together, and all the variables

5y-12

Back to the equation:

-(5y-12)



We add all the numbers together, and all the variables

6y-(5y-12)-28=0

We get rid of parentheses

6y-5y+12-28=0

We add all the numbers together, and all the variables

y-16=0

We move all terms containing y to the left, all other terms to the right

y=16

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