-6(y+3)=4(y+2)-5(2y+3)

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Solution for -6(y+3)=4(y+2)-5(2y+3) equation:


Simplifying
-6(y + 3) = 4(y + 2) + -5(2y + 3)

Reorder the terms:
-6(3 + y) = 4(y + 2) + -5(2y + 3)
(3 * -6 + y * -6) = 4(y + 2) + -5(2y + 3)
(-18 + -6y) = 4(y + 2) + -5(2y + 3)

Reorder the terms:
-18 + -6y = 4(2 + y) + -5(2y + 3)
-18 + -6y = (2 * 4 + y * 4) + -5(2y + 3)
-18 + -6y = (8 + 4y) + -5(2y + 3)

Reorder the terms:
-18 + -6y = 8 + 4y + -5(3 + 2y)
-18 + -6y = 8 + 4y + (3 * -5 + 2y * -5)
-18 + -6y = 8 + 4y + (-15 + -10y)

Reorder the terms:
-18 + -6y = 8 + -15 + 4y + -10y

Combine like terms: 8 + -15 = -7
-18 + -6y = -7 + 4y + -10y

Combine like terms: 4y + -10y = -6y
-18 + -6y = -7 + -6y

Add '6y' to each side of the equation.
-18 + -6y + 6y = -7 + -6y + 6y

Combine like terms: -6y + 6y = 0
-18 + 0 = -7 + -6y + 6y
-18 = -7 + -6y + 6y

Combine like terms: -6y + 6y = 0
-18 = -7 + 0
-18 = -7

Solving
-18 = -7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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