-6(y-3y)+6=-4(2y-y)+9+15y

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Solution for -6(y-3y)+6=-4(2y-y)+9+15y equation: 



-6(y-3y)+6=-4(2y-y)+9+15y

We move all terms to the left:

-6(y-3y)+6-(-4(2y-y)+9+15y)=0

We add all the numbers together, and all the variables

-6(-2y)-(-4(+y)+9+15y)+6=0

We multiply parentheses

12y-(-4(+y)+9+15y)+6=0



We calculate terms in parentheses: -(-4(+y)+9+15y), so:

-4(+y)+9+15y

determiningTheFunctionDomain
-4(+y)+15y+9

We add all the numbers together, and all the variables

15y-4(+y)+9

We multiply parentheses

15y-4y+9

We add all the numbers together, and all the variables

11y+9

Back to the equation:

-(11y+9)



We get rid of parentheses

12y-11y-9+6=0

We add all the numbers together, and all the variables

y-3=0

We move all terms containing y to the left, all other terms to the right

y=3

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