-6(z-2)+4(3-6z)=-36

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Solution for -6(z-2)+4(3-6z)=-36 equation: 



-6(z-2)+4(3-6z)=-36

We move all terms to the left:

-6(z-2)+4(3-6z)-(-36)=0

We add all the numbers together, and all the variables

-6(z-2)+4(-6z+3)-(-36)=0

We add all the numbers together, and all the variables

-6(z-2)+4(-6z+3)+36=0

We multiply parentheses

-6z-24z+12+12+36=0

We add all the numbers together, and all the variables

-30z+60=0

We move all terms containing z to the left, all other terms to the right

-30z=-60

z=-60/-30

z=+2

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