-6+(5-4m)=-7+(2-m)

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Solution for -6+(5-4m)=-7+(2-m) equation: 



-6+(5-4m)=-7+(2-m)

We move all terms to the left:

-6+(5-4m)-(-7+(2-m))=0

We add all the numbers together, and all the variables

(-4m+5)-(-7+(-1m+2))-6=0

We get rid of parentheses

-4m-(-7+(-1m+2))+5-6=0



We calculate terms in parentheses: -(-7+(-1m+2)), so:

-7+(-1m+2)

determiningTheFunctionDomain
(-1m+2)-7

We get rid of parentheses

-1m+2-7

We add all the numbers together, and all the variables

-1m-5

Back to the equation:

-(-1m-5)



We add all the numbers together, and all the variables

-4m-(-1m-5)-1=0

We get rid of parentheses

-4m+1m+5-1=0

We add all the numbers together, and all the variables

-3m+4=0

We move all terms containing m to the left, all other terms to the right

-3m=-4

m=-4/-3

m=1+1/3

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