-6+(x/4)-4=(3/2)x+18

Solution for -6+(x/4)-4=(3/2)x+18 equation:

-6+(x/4)-4=(3/2)x+18

We move all terms to the left:

-6+(x/4)-4-((3/2)x+18)=0


Domain of the equation: 2)x+18)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+x/4)-((+3/2)x+18)-6-4=0

We add all the numbers together, and all the variables

(+x/4)-((+3/2)x+18)-10=0

We get rid of parentheses

x/4-((+3/2)x+18)-10=0

We calculate fractions


2x^2/8x+()/8x-10=0

We multiply all the terms by the denominator


2x^2-10*8x+()=0

We add all the numbers together, and all the variables

2x^2-10*8x=0

Wy multiply elements

2x^2-80x=0

a = 2; b = -80; c = 0;
Δ = b2-4ac
Δ = -802-4·2·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-80}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+80}{2*2}=\frac{160}{4}
=40
$