-6+-(4-(2-3t))=4(t+1)

Solution for -6+-(4-(2-3t))=4(t+1) equation:

-6+-(4-(2-3t))=4(t+1)

We move all terms to the left:

-6+-(4-(2-3t))-(4(t+1))=0

We add all the numbers together, and all the variables

-(4-(-3t+2))-(4(t+1))-6+=0

We add all the numbers together, and all the variables

-(4-(-3t+2))-(4(t+1))=0


We calculate terms in parentheses: -(4-(-3t+2)), so:

4-(-3t+2)

determiningTheFunctionDomain
-(-3t+2)+4

We get rid of parentheses

3t-2+4

We add all the numbers together, and all the variables

3t+2

Back to the equation:

-(3t+2)



We calculate terms in parentheses: -(4(t+1)), so:

4(t+1)

We multiply parentheses

4t+4

Back to the equation:

-(4t+4)


We get rid of parentheses

-3t-4t-2-4=0

We add all the numbers together, and all the variables

-7t-6=0

We move all terms containing t to the left, all other terms to the right

-7t=6

t=6/-7

t=-6/7