-6+2/5f=10

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Solution for -6+2/5f=10 equation: 



-6+2/5f=10

We move all terms to the left:

-6+2/5f-(10)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We add all the numbers together, and all the variables

2/5f-16=0

We multiply all the terms by the denominator


-16*5f+2=0

Wy multiply elements

-80f+2=0

We move all terms containing f to the left, all other terms to the right

-80f=-2

f=-2/-80

f=1/40

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