-6+7=3(2p2-3)-4(-10+4p)

Solution for -6+7=3(2p2-3)-4(-10+4p) equation:

-6+7=3(2p^2-3)-4(-10+4p)

We move all terms to the left:

-6+7-(3(2p^2-3)-4(-10+4p))=0

We add all the numbers together, and all the variables

-(3(2p^2-3)-4(4p-10))-6+7=0

We add all the numbers together, and all the variables

-(3(2p^2-3)-4(4p-10))+1=0


We calculate terms in parentheses: -(3(2p^2-3)-4(4p-10)), so:

3(2p^2-3)-4(4p-10)

We multiply parentheses

6p^2-16p-9+40

We add all the numbers together, and all the variables

6p^2-16p+31

Back to the equation:

-(6p^2-16p+31)


We get rid of parentheses

-6p^2+16p-31+1=0

We add all the numbers together, and all the variables

-6p^2+16p-30=0

a = -6; b = 16; c = -30;
Δ = b2-4ac
Δ = 162-4·(-6)·(-30)
Δ = -464
Delta is less than zero, so there is no solution for the equation