-6+8b=(b-7)+2

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Solution for -6+8b=(b-7)+2 equation: 



-6+8b=(b-7)+2

We move all terms to the left:

-6+8b-((b-7)+2)=0



We calculate terms in parentheses: -((b-7)+2), so:

(b-7)+2

We get rid of parentheses

b-7+2

We add all the numbers together, and all the variables

b-5

Back to the equation:

-(b-5)



We get rid of parentheses

8b-b+5-6=0

We add all the numbers together, and all the variables

7b-1=0

We move all terms containing b to the left, all other terms to the right

7b=1

b=1/7

b=1/7

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