-6-(-3z-2)=5z-4(2z+1)

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Solution for -6-(-3z-2)=5z-4(2z+1) equation: 



-6-(-3z-2)=5z-4(2z+1)

We move all terms to the left:

-6-(-3z-2)-(5z-4(2z+1))=0

We get rid of parentheses

3z-(5z-4(2z+1))+2-6=0



We calculate terms in parentheses: -(5z-4(2z+1)), so:

5z-4(2z+1)

We multiply parentheses

5z-8z-4

We add all the numbers together, and all the variables

-3z-4

Back to the equation:

-(-3z-4)



We add all the numbers together, and all the variables

3z-(-3z-4)-4=0

We get rid of parentheses

3z+3z+4-4=0

We add all the numbers together, and all the variables

6z=0

z=0/6

z=0

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