-6-12(11n+8)=-10(n-4)

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Solution for -6-12(11n+8)=-10(n-4) equation: 



-6-12(11n+8)=-10(n-4)

We move all terms to the left:

-6-12(11n+8)-(-10(n-4))=0

We multiply parentheses

-132n-(-10(n-4))-96-6=0



We calculate terms in parentheses: -(-10(n-4)), so:

-10(n-4)

We multiply parentheses

-10n+40

Back to the equation:

-(-10n+40)



We add all the numbers together, and all the variables

-132n-(-10n+40)-102=0

We get rid of parentheses

-132n+10n-40-102=0

We add all the numbers together, and all the variables

-122n-142=0

We move all terms containing n to the left, all other terms to the right

-122n=142

n=142/-122

n=-1+10/61

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