-6-2/3d+13/6d=-4

Solution for -6-2/3d+13/6d=-4 equation:

-6-2/3d+13/6d=-4

We move all terms to the left:

-6-2/3d+13/6d-(-4)=0


Domain of the equation: 3d!=0

d!=0/3

d!=0

d∈R



Domain of the equation: 6d!=0

d!=0/6

d!=0

d∈R


We add all the numbers together, and all the variables

-2/3d+13/6d-2=0

We calculate fractions


(-12d)/18d^2+39d/18d^2-2=0

We multiply all the terms by the denominator


(-12d)+39d-2*18d^2=0

We add all the numbers together, and all the variables

39d+(-12d)-2*18d^2=0

Wy multiply elements

-36d^2+39d+(-12d)=0

We get rid of parentheses

-36d^2+39d-12d=0

We add all the numbers together, and all the variables

-36d^2+27d=0

a = -36; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-36)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-36}=\frac{-54}{-72}
=3/4
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-36}=\frac{0}{-72}
=0
$