-6.76+b2=9

Solution for -6.76+b2=9 equation:

-6.76+b2=9

We move all terms to the left:

-6.76+b2-(9)=0

We add all the numbers together, and all the variables

b^2-15.76=0

a = 1; b = 0; c = -15.76;
Δ = b2-4ac
Δ = 02-4·1·(-15.76)
Δ = 63.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{63.04}}{2*1}=\frac{0-\sqrt{63.04}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{63.04}}{2*1}=\frac{0+\sqrt{63.04}}{2}
=\frac{\sqrt{}}{2}
$