-6/(v-2)=4(5v-10)+1

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Solution for -6/(v-2)=4(5v-10)+1 equation: 


D( v )

v-2 = 0

v-2 = 0

v-2 = 0

v-2 = 0 // + 2

v = 2

v in (-oo:2) U (2:+oo)

-6/(v-2) = 4*(5*v-10)+1 // - 4*(5*v-10)+1

-6/(v-2)-(4*(5*v-10))-1 = 0

-6/(v-2)-4*(5*v-10)-1 = 0

(-4*(5*v-10)*(v-2))/(v-2)-6/(v-2)+(-1*(v-2))/(v-2) = 0

-4*(5*v-10)*(v-2)-1*(v-2)-6 = 0

80*v-20*v^2-v-86+2 = 0

79*v-20*v^2-84 = 0

79*v-20*v^2-84 = 0

79*v-20*v^2-84 = 0

DELTA = 79^2-(-84*(-20)*4)

DELTA = -479

DELTA < 0

1 = 0

1/(v-2) = 0

1/(v-2) = 0 // * v-2

1 = 0

v belongs to the empty set

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