-6/10x+(-7/10x)+1/2x=-56

Solution for -6/10x+(-7/10x)+1/2x=-56 equation:

-6/10x+(-7/10x)+1/2x=-56

We move all terms to the left:

-6/10x+(-7/10x)+1/2x-(-56)=0


Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R



Domain of the equation: 10x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

-6/10x+(-7/10x)+1/2x+56=0

We get rid of parentheses

-6/10x-7/10x+1/2x+56=0

We calculate fractions


(-14x-6)/20x^2+10x/20x^2+56=0

We multiply all the terms by the denominator


(-14x-6)+10x+56*20x^2=0

We add all the numbers together, and all the variables

10x+(-14x-6)+56*20x^2=0

Wy multiply elements

1120x^2+10x+(-14x-6)=0

We get rid of parentheses

1120x^2+10x-14x-6=0

We add all the numbers together, and all the variables

1120x^2-4x-6=0

a = 1120; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·1120·(-6)
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26896}=164$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-164}{2*1120}=\frac{-160}{2240}
=-1/14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+164}{2*1120}=\frac{168}{2240}
=3/40
$