-6/7(21x-28)=40-2x

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Solution for -6/7(21x-28)=40-2x equation: 



-6/7(21x-28)=40-2x

We move all terms to the left:

-6/7(21x-28)-(40-2x)=0



Domain of the equation: 7(21x-28)!=0

x∈R



We add all the numbers together, and all the variables

-6/7(21x-28)-(-2x+40)=0

We get rid of parentheses

-6/7(21x-28)+2x-40=0

We multiply all the terms by the denominator


2x*7(21x-28)-40*7(21x-28)-6=0

Wy multiply elements

14x^2(2-280x(2-6=0

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