-6/u+3=(-1/4u+12)+2

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Solution for -6/u+3=(-1/4u+12)+2 equation:


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

3-6/u = (-1/4)*u+2+12 // - (-1/4)*u+2+12

3-((-1/4)*u)-6/u-12-2 = 0

(1/4)*u-6/u-12-2+3 = 0

1/4*u^1-6*u^-1-11*u^0 = 0

(1/4*u^2-11*u^1-6*u^0)/(u^1) = 0 // * u^2

u^1*(1/4*u^2-11*u^1-6*u^0) = 0

u^1

(1/4)*u^2-11*u-6 = 0

(1/4)*u^2-11*u-6 = 0

DELTA = (-11)^2-(-6*4*(1/4))

DELTA = 127

DELTA > 0

u = (127^(1/2)+11)/(2*(1/4)) or u = (11-127^(1/2))/(2*(1/4))

u = 2*(127^(1/2)+11) or u = 2*(11-127^(1/2))

u in { 2*(11-127^(1/2)), 2*(127^(1/2)+11)}

u in { 2*(11-127^(1/2)), 2*(127^(1/2)+11) }

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