-64+2(y-4)=8(y+3)

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Solution for -64+2(y-4)=8(y+3) equation: 



-64+2(y-4)=8(y+3)

We move all terms to the left:

-64+2(y-4)-(8(y+3))=0

We multiply parentheses

2y-(8(y+3))-8-64=0



We calculate terms in parentheses: -(8(y+3)), so:

8(y+3)

We multiply parentheses

8y+24

Back to the equation:

-(8y+24)



We add all the numbers together, and all the variables

2y-(8y+24)-72=0

We get rid of parentheses

2y-8y-24-72=0

We add all the numbers together, and all the variables

-6y-96=0

We move all terms containing y to the left, all other terms to the right

-6y=96

y=96/-6

y=-16

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