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-64+8x=2(2/5x+5)
We move all terms to the left:
-64+8x-(2(2/5x+5))=0
Domain of the equation: 5x+5))!=0We multiply all the terms by the denominator
x∈R
8x*5x-64*5x+5))-(2(2+5))=0
We add all the numbers together, and all the variables
8x*5x-64*5x+5))-(27)=0
We add all the numbers together, and all the variables
8x*5x-64*5x=0
Wy multiply elements
40x^2-320x=0
a = 40; b = -320; c = 0;
Δ = b2-4ac
Δ = -3202-4·40·0
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{102400}=320$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-320}{2*40}=\frac{0}{80} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+320}{2*40}=\frac{640}{80} =8 $
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